Question

помогите пожалуйста решить​

Answer 1

Ответ:

$\frac{5b + 3 - (6b - 1)}{(b - 4)(b + 4)} \\ \\ \frac{5b + 3 - 6b + 1}{(b - 4)(b + 4)} \\ \\ \frac{ - (b - 4)}{(b - 4)(b + 4)} \\ \\ - \frac{1}{b + 4}$

$- \frac{1}{ - 3 + 4} = -1$

Answer 2

$\displaystyle\bf\\\frac{5b+3}{b^{2} -16} -\frac{6b-1}{b^{2} -16} =\frac{5b+3+1-6b}{b^{2} -16}=\frac{4-b}{(b-4)(b+4)} =\\\\\\=-\frac{b-4}{(b-4)(b+4)} =-\frac{1}{b+4}\\\\b=-3\\\\-\frac{1}{b+4} =-\frac{1}{-3+4} } =-1$