Question

Помогите вычислить! Тема степени

Answer 1

$a)30 {}^{ - 4.7} \times 6 {}^{5.7} \div 5 {}^{ - 3.7} =$

$30 {}^{ - \frac{47}{10} } \times 6 {}^{5.7} \times 5 {}^{3.7} =$

$\frac{1}{30 {}^{ \frac{47}{10} } } \times 6 {}^{5.7} \times 5 {}^{3.7} =$

$\frac{6 {}^{5.7} \times 5 {}^{3.7} }{30 {}^{ \frac{47}{10} } } =$

$\frac{6 {}^{ \frac{57}{10} } \times 5 {}^{ \frac{37}{10} } }{ \sqrt[10]{30 {}^{47} } } =$

$\frac{ \sqrt[10]{6 {}^{57} } \sqrt[10]{5 {}^{37} } }{30 {}^{4} \times \sqrt[10]{30 {}^{7} } } =$

$\frac{ \sqrt[10]{6 {}^{57} \times 5 {}^{37} } }{5 {}^{4} \times 6 {}^{4} \times \sqrt[10]{30 {}^{7} } } =$

$\frac{6 {}^{5} \times 5 {}^{3} \times \sqrt[10]{6 {}^{7} \times 5 {}^{7} } }{5 {}^{4} \times 6 {}^{4} \times \sqrt[10]{30 {}^{7} } } = \frac{6 \sqrt[10]{30 {}^{7} } }{5 \sqrt[10]{30 {}^{7} } } = \frac{6}{5}$

Answer 2

Ответ:

1,2

Объяснение:

$\displaystyle\bf\\30^{-4,7}\cdot6^{5,7}:5^{-3,7}=(6\cdot5)^{-4,7}\cdot6^{5,7}:5^{-3,7}=\\\\=6^{-4,7+5,7}\cdot5^{-4,7-(-3,7)}=6\cdot5^{-1}=6:5=1,2$