Question

помогите пожалуйста ​

Answer 1

Ответ:

$\frac{1}{8} *(\frac{4}{3}-x ) = \frac{1}{4} - \frac{1}{3} ;\\\frac{4}{3} - x = 8(\frac{3-4}{12} );\\-x = 8*(-\frac{1}{12}) - \frac{4}{3};\\-x = -\frac{2}{3} - \frac{4}{3};\\-x = -2;\\x = 2;$