Question

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Answer 1

Ответ:

$\frac{23 + c {}^{2} }{c {}^{12} } - \frac{1}{c {}^{10} } =\frac{23+c^{2}}{c^{12}}-\frac{c^{2}}{c^{12}} =\frac{23+c^{2}-c^{2}}{c^{12}} =\frac{23}{c^{12}}$

Answer 2

Объяснение:

23+с^2/с^12 - 1/с^10 = 23+с^2/с^12 - с^2/с^12 = 23+с^2-с^2/с^12 = 23/с^12