Question

1/3х(х+9)=1/8х(х-16)

Answer 1

ответ приведен на фото

Answer 2

$\frac{1}{3}x(x+9) = \frac{1}{8}x(x-16)\\\frac{x^{2} +9x}{3} = \frac{x^{2} -16x}{8}\\8(x^{2} +9x) = 3(x^{2} -16x)\\8x^{2} +72x = 3x^{2} -48x\\5x^{2} + 120x = 0\\5x(x+24) = 0\\\\5x = 0\\x+24 = 0\\\\x = 0\\x = -24$