Question

x3-8÷9x2-16÷x2+2x+4÷3x-4, якщо x=-3!СРОЧНО ПОЖАЛУСТА!!!!!​

Answer 1

$\displaystyle\bf\\\frac{x^{3} -8}{9x^{2} -16} :\frac{x^{2} +2x+4}{3x-4} =\frac{(x-2)(x^{2}+2x+4) }{(3x-4)(3x+4)} \cdot\frac{3x-4}{x^{2} +2x+4} =\\\\\\=\frac{x-2}{3x+4} \\\\\\x=-3\\\\\\\frac{x-2}{3x+4} =\frac{-3-2}{3\cdot(-3)+4} =\frac{-5}{-9+4} =\frac{-5}{-5} =1$