Question

ПОМОГИТЕ НОМЕР 5 ПОЖАЛУЙСТА!!!!!!

Answer 1

Ответ:

-m

Объяснение:

$\displaystyle\\\frac{36-m^2}{m-8}\cdot\bigg(\frac{m}{m-6} -\frac{2m}{m^2-12m+36} \bigg)+\frac{12m}{m-6} =\\\\\\=\frac{(6-m)(6+m)}{m-8}\cdot\bigg(\frac{m}{m-6} -\frac{2m}{(m-6)^2} \bigg)+\frac{12m}{m-6} =\\\\\\= \frac{(6-m)(6+m)}{m-8}\cdot\frac{m^2-6m-2m}{(m-6)^2} +\frac{12m}{m-6} =\\\\\\=\frac{-(6+m)}{m-8}\cdot\frac{m^2-8m}{m-6} +\frac{12m}{m-6} =\\\\\\=\frac{-6-m}{m-8}\cdot\frac{m(m-8)}{m-6} +\frac{12m}{m-6} =\\\\\\=\frac{m(-6-m)}{m-6} +\frac{12m}{m-6} =\\\\\\=\frac{-6m-m^2+12m}{m-6}=$

$=\dfrac{-m^2+6m}{m-6}=\dfrac{-m(m-6)}{m-6} =-m$