Question

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(9-х)(-2х+27)=0​

Answer 1

(9-х)(-2х+27)=0

$\left \{ {{9-x=0} \atop {-2x+27=0}} \right. \left \{ {{-x=-9 |: (-1)} \atop {-2x=-27 |: (-2)}} \right. \left \{ {{x=9} \atop {x=13,5}} \right.$

Answer 2

$(9-x)(-2x+27)=0\\1)~9-x=0\to~x_1=9;\\2)~-2x+27=0;~-2x=-27\to x_2=\frac{27}{2} .$