Question

$3 \frac{1}{4} - ( \frac{1}{3} ) {}^{2} \times ( - 1 \frac{1}{2} ) {}^{2} - 25 \times 3 \times 0.04 =$
помогите решить ​

Answer 1

Пошаговое объяснение:

$3 \frac{1}{4} - ( \frac{1}{3} ) {}^{2} \times ( - 1 \frac{1}{2} ) {}^{2} - 25 \times 3 \times 0.04= \frac{12+1}{4}-\left(\frac{1}{3}\right)^{2}\left(-\frac{1\times 2+1}{2}\right)^{2}-25\times 3\times 0.04 =\frac{13}{4}-\left(\frac{1}{3}\right)^{2}\left(-\frac{1\times 2+1}{2}\right)^{2}-25\times 3\times 0.04 =\frac{13}{4}-\frac{1}{9}\left(-\frac{1\times 2+1}{2}\right)^{2}-25\times 3\times 0.04 =\frac{13}{4}-\frac{1}{9}\left(-\frac{2+1}{2}\right)^{2}-25\times 3\times 0.04 =\frac{13}{4}-\frac{1}{9}\left(-\frac{3}{2}\right)^{2}-25\times 3\times 0.04 =\frac{13}{4}-\frac{1}{9}\times \left(\frac{9}{4}\right)-25\times 3\times 0.04 =\frac{13}{4}-\frac{1}{4}-25\times 3\times 0.04 =3-25\times 3\times 0.04 =3-75\times 0.04 =3-3 =0$

Answer 2

Ответ:

0

Пошаговое объяснение:

13/4-(1/3 × 3/2)²-25×3×0,04= 13/4-(1/3 × 3/2)²-3= 13/4-(1/2)²-3= 13/4-1/4-3=

= 12/4 -3= 3-3=0