Question

Представьте в виде многочлена: (5+a)³ ; (2+n²)³ ; (3+1_3b)³ ; (5x+4m)³ ; (3x+2y)³ (1_3+k)³

Answer 1

(5+a)³=a³+15a²+75a+125

(2+n²)=n⁶+6n⁴+12n²+8

(3+1/3n)³=27+9b+b²+1/27b³

(5x+4m)³=125x³+300mx²+240m²x+64m³

(3x+2y)³=27x³+54x²y+36xy²+8y³

(1/3+k)³=1/27+1/3x+x²+x³