Question

(3целых-12/17+4целых-5/21) - 1 целая 12/17​

Answer 1

Ответ:

$=(3+4)+(\frac{12}{17}+\frac{5}{21})-\frac{29}{17}=(7+\frac{337}{357})-\frac{29}{17}=7\frac{337}{357}-\frac{29}{17}=\frac{2499+337}{357}-\frac{29}{17}=\frac{2836}{357} -\frac{29}{17}=\frac{131}{21} =6\frac{5}{21}$

Пошаговое объяснение:

Answer 2

3 12/17 + 4 5/21 - 1 12/17 = 6целых 5/21