Question

Решить 0,7 в степени 3-5х=1

Answer 1

Объяснение:

$0.7 ^ { 3-5x } =1\\0.7^{-5x+3}=1 \\\log(0.7^{-5x+3})=\log(1) \\ \left(-5x+3\right)\log(0.7)=\log(1) \\-5x+3=\frac{\log(1)}{\log(0.7)} \\ -5x+3=\log_{0.7}\left(1\right) \\-5x=-3 \\ x=\frac{3}{5}=0.6$

Answer 2

$0.7 {}^{3 - 5x} = 1 \\ 0.7 {}^{3 - 5x} = 0.7 {}^{0} \\ 3 - 5x = 0 \\ - 5x = - 3 \\ x = \frac{3}{5} = 0.6$