Question

Умоляю помогите 100 баллов

Answer 1

$\tt\bigg(\sqrt{3} -1\bigg)\cdot\bigg(2+\sqrt{3} \bigg)=2\cdot\sqrt{3} +\sqrt{3} \cdot\sqrt{3} -2-\sqrt{3} =2\cdot\sqrt{3} +3-2-\sqrt{3} =\underbrace{ \bigg(2\cdot\sqrt{3}}_{2\cdot\sqrt{3} -1\sqrt{3} =(2-1)\sqrt{3}=1\sqrt{3} =\sqrt{3} } -\sqrt{3}\bigg)+\underbrace{\bigg(3-2\bigg)} _1= \boxed{\bf\sqrt{3} +1} ;$

$\sf\displaystyle\frac{\sqrt{2}-5 ^{\bigg(3} }{4} -\frac{1-\sqrt{2}^{\bigg(2} }{6} ~~=\frac{3\cdot\bigg(\sqrt{2} -5\bigg)-2\bigg(1-\sqrt{2}\bigg) }{12} =\frac{3\sqrt{2}-15-2+2\sqrt{2} }{12} =\boxed{\bf\frac{5\sqrt{2}-17 }{12} } .$

Answer 2

г) 2√3+√3√3-2-√3
2√3+3-2-√3
√3+3-2
√3+1
≈2,73205