Question

16х квадрате+21х-22=0​

Answer 1

16x²+21x-22=0

a=16,b=21,c= -22

D=b²-4ac=21²-4*16*(-22)=1849

$x1 = \frac{ - 21 - \sqrt{1849} }{2 \times 16} = \frac{ - 64}{2 \times 16} = \frac{ - 32}{16} = - 2$

$x2 = \frac{ - 21 + \sqrt{1849} }{2 \times 16} = \frac{ - 21 + 43}{2 \times 16} = \frac{22}{2 \times 16} = \frac{11}{16}$

Ответ: x1= -2;x2=11/16

Answer 2

Ответ:

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Объяснение:

$16x^{2} +21x-22=0\\D=441-4*16*(-22)=1849\\x_{1}= \frac{-21-43}{32}=\frac{-64}{32}= -2\\x_{2}=\frac{-21*43}{32}=\frac{22}{32}=\frac{11}{16}$