Question

решите пожалуйста уравнение срочно​

Answer 1

$\frac{y {}^{2} + 3y}{5} = \frac{10 - y}{2} - \frac{3y {}^{2} + 8y}{14}$

$14y {}^{2} + 42y = 350 - 35y - 15y {}^{2} - 40y$

$14y {}^{2} + 42y = 350 - 75y - 15y {}^{2}$

$14y {}^{2} + 42y - 350 + 75y + 15y {}^{2} = 0$

$29y {}^{2} + 117y - 350 = 0$

$29y {}^{2} + 175y - 58y - 350 = 0$

$y \times (29y + 175) - 2(29y + 175) = 0$

$(29y + 175) \times (y - 2) = 0$

$29y + 175 = 0$

$y - 2 = 0$

$y = - \frac{175}{29} \\ y = 2$

$y _{1} = - \frac{175}{29} ,y_2 = 2$