Question

Амалды орында:1)8+1/24-(2 5/6+3 7/8)=? пжжжж пжж​

Answer 1

Ответ:

1) 8+1/24-(2 5/6+3 7/8)=

$8+\frac{1}{24}-(2\frac{5}{6}+3\frac{7}{8})= 8+\frac{1}{24}-((2+3)+(\frac{5}{6}+\frac{7}{8}))= 8+\frac{1}{24}-(5+(\frac{5*4+7*3}{24}))= \\\\=8+\frac{1}{24}-(5+(\frac{20+21}{24}))= 8+\frac{1}{24}-(5+\frac{41}{24})= 8+\frac{1}{24}-(5+1\frac{17}{24})= \\\\=8+\frac{1}{24}-(5+1+\frac{17}{24})= 8+\frac{1}{24}-(6+\frac{17}{24})= 8+\frac{1}{24}-6\frac{17}{24}= 8+\frac{1}{24}-\frac{24*6+17}{24}=$

$=8+\frac{1}{24}-\frac{144+17}{24}= 8+\frac{1}{24}-\frac{161}{24}= 8+\frac{1-161}{24} = 8+\frac{-160}{24} =8+\frac{-20}{3} =\frac{8*3+(-20)}{3} =\\\\=\frac{24-20}{3}=\frac{4}{3} =1 \frac{1}{3}.$