Question

16х²-9=0 через дискриминат​

Answer 1

Ответ:

$16 {x}^{2} = 0 + 9 \\ {16x}^{2} = 9 \\ {x}^{2} = 9 \div 16 \\ {x}^{2} = \frac{9}{16} \\ x1 = \frac{3}{4} \\ x2 = - \frac{3}{4}$

Answer 2

$16x^2-9=0\\16x^2+0x-9=0\\16x^2+0x+(-9)=0\\a=16;b=0;c=-9\\D=b^2-4ac=0^2-4*16*(-9)=576;\\\displaystyle x_1=(-b-\sqrt{D} )/2a=\frac{-\sqrt{576} }{2*16} = -24:32= ~-0,75\\x_2=(-b+\sqrt{D} )/2a=\frac{\sqrt{576} }{2*16} =24:32=~0,75$