Question

помогите кто с дробями дружит!

Answer 1

Ответ:

$- \frac{4}{49} a {}^{7} b + \frac{1}{7} a {}^{7} b + \frac{1}{49} a {}^{7} b = \frac{ - 4a {}^{7} b + 7a {}^{7} b + a {}^{7}b }{49} = \frac{4a {}^{7}b }{49} = \frac{4}{49} a {}^{7} b$

Answer 2

$\displaystyle-\frac{4}{49}a^7b+\frac{1}{7}a^7b+\frac{1}{49}a^7b==-\frac{4a^7b}{49}+\frac{a^7b}{7}+\frac{a^7b}{49}=-\frac{4a^7b}{49}+\frac{7a^7b}{7*7}+\frac{a^7b}{49}=\\ \\ -\frac{4a^7b}{49}+\frac{7a^7b}{49}+\frac{a^7b}{49}=\frac{-4a^7b+7a^7b+a^7b}{49}=\frac{4a^7b}{49}=\frac{4}{49}a^7b$