Question

их сумма равна 488 и одно меньше другого в 7 раз​

Answer 1

Ответ:

х+х:7=488

7х+х=7*488

8х=3416

х=3416:8

х=427

427:7=61

Answer 2

Решение:

$\left \{ {{x_1 + x_2 = 488} \atop {\frac{x_1}{x_2} = 7}} \right. \\\\\left \{ {{x_1 + x_2 = 488} \atop {x_1 = 7x_2} \right. \\\\\left \{ {{7x_2 + x_2 = 488} \atop {x_1 = 7x_2} \right. \\\\\left \{ {{8x_2 = 488} \atop {x_1 = 7x_2} \right. \\\\\left \{ {{x_2 = 488/8} \atop {x_1 = 7x_2} \right. \\\\\left \{ {{x_2 = 61} \atop {x_1 = 7*61} \right. \\\\\left \{ {{x_2 = 61} \atop {x_1 = 427} \right.$

Ответ: числа 61 и 427.