Question

Помогите пожалуйста 40 баллов

1) 3√2(5√2-√32) = 
 (4-5√2)$^{2}$ = 
 (√7 - 2√3)(√7 + 2√3) = 

2) $frac{1}{5}$√300 - 4√$frac{3}{16}$ - √75
(3√2-1)(√8 + 2)
(√5 + 2$)^{2}$ - (3 - √5$)^{2}$

Answer 1

$1) 3sqrt{2}(5sqrt{2}- sqrt{32})=15*2-3 sqrt{32*2}=30-24=6 \ (4-5 sqrt{2})^{2}=16-40 sqrt{2}+50=66-40 sqrt{2} \ ( sqrt{7}-2sqrt{3})( sqrt{7}+2sqrt{3})=7-12=-5$
$2) frac{1}{5} sqrt{300}-4 sqrt{ frac{3}{16}}- sqrt{75}=frac{1}{5}*10sqrt{3}-sqrt{ frac{3}{16}*16}- sqrt{5^{2}*3}= \ =2sqrt{3}-sqrt{3}-5sqrt{3}=-4 sqrt{3} \ (3sqrt{2}-1)(sqrt{8}+2)=(3sqrt{2}-1)(2sqrt{2}+2)=6*2-2sqrt{2}+6sqrt{2}-2= \ =10+4sqrt{2} \ ( sqrt{5}+2 )^{2}-(3- sqrt{5})^{2}=5+4sqrt{5}+4-9+12sqrt{5}-5=16sqrt{5}-5$