Question

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Answer 1

$\displaystyle1\frac{2}{9}:3\frac{2}{3}+4\frac{2}{5}:(\frac{7}{10}+2\frac{3}{5})-(\frac{3}{17}-1\frac{16}{17}:11)=\frac{11}{9}:\frac{11}{3}+\frac{22}{5}:(\frac{7}{10}+\frac{13}{5})-(\frac{3}{17}-\\ \\ \frac{33}{17}*\frac{1}{11})=\frac{11}{9}*\frac{3}{11}+\frac{22}{5}:\frac{33}{10}-(\frac{3}{17}-\frac{3}{17})=\frac{1}{3}+\frac{22}{5}*\frac{10}{33}-0=\\ \\ \frac{1}{3}+2*\frac{2}{3}=\frac{1}{3}+\frac{4}{3}=\frac{5}{3}=1\frac{2}{3}$