Question

5x2+9x-18=0

Только 6 помогите​

Answer 1

$\displaystyle 5x^2+9x-18=0\\5x^2+15x-6x-18=0\\5x(x+3)-6(x+3)=0\\(x+3)(5x-6)=0\\x+3=0,5x-6=0\\\\ x_{1}=-3,x_{2}=\frac{6}{5}=1,2$