Question

sin 45°-2cos 45°×2tg 60° =​

Answer 1

$\sin(45) - 2 \cos(45) \times 2 \tg(60) = \frac{ \sqrt{2} }{2} - 2 \times \frac{ \sqrt{2} }{2} \times 2 \times \sqrt{3} = \frac{ \sqrt{2} }{2} - 2\sqrt{6}$