Question

Помогите пожалуйста!!

Answer 1

$t {}^{2} + 10t + 16 = 0 \\ a = 1~~~~~~~~~~b = 10~~~~~~~~~~c = 16 \\ D = b {}^{2} - 4ac = 10 {}^{2} - 4 \times 1 \times 16 = 100 - 64 = 36 \\ t1 = \frac{ - 10 + \sqrt{36} }{2 \times 1} = \frac{ - 10 + 6}{2} = \frac{ - 4}{2} = - 2 \\ t2 = \frac{ - 10 - \sqrt{36} }{2 \times 1} = \frac{ - 10 - 6}{2} = \frac{ - 16}{2} = - 8 \\ Ответ:~t1= -2~~~~~~~t2= -8$