Question

Докажите тождество:
x2-12x+32=(x-8)(x-4)

Answer 1

x2-12x+32=(x-8)(x-4)
x2-12x+32=x2-4x-8x+32
x2-12x+32=x2-12x+32

Answer 2

$x^{2} -12x+32=(x-8)(x-4)$
$x^{2} -12x+32= x^{2} -4x-8x+32$
$x^{2} - x^{2} -12x+12x+32-32=0$
$0=0$