Question

СРОЧНО! пожалуйста помогите!!!
4√(x^2+3x-6)=18-3x-x^2​

Answer 1

$4 \sqrt{x {}^{2} + 3x - 6 } = 18 - 3x - x {}^{2} \\ 16x {}^{2} + 48x - 96 = 324 - 27x {}^{2} + x {}^{4} - 108x + 6x {}^{3} \\ 43x {}^{2} + 156x - 420 - x {}^{4} - 6x {}^{3} = 0 \\ - x {}^{4} - 6x {}^{3 } + 43x {}^{2} + 156x - 420 = 0 \\ \\ - x {}^{3} \times (x - 2) - 8x {}^{2} \times (x - 2) + 27x \times (x - 2) + 210(x - 2) = 0 \\ - (x - 2)( {}^{3} + 8x {}^{2} - 27x - 210) = 0 \\ (x - 2)(x + 5)(x {}^{2} + 3x - 42) = 0 \\ x - 2 = 0 \\ x + 5 = 0 \\ x {}^{2} + 3x - 42 = 0 \\ x1 = - 5 \: \: x2 = 2$