Question

помогите с алгеброй пожалуйста!!! ​

Answer 1

$1) \sqrt{13 {}^{2} - 12 {}^{2} } = \sqrt{1 \times 25} = \sqrt{25} = 5 \\ 2) \sqrt{25 {}^{2} - 24 {}^{2} } = \sqrt{1 \times 49} = \sqrt{49} = 7 \\ 3) \sqrt{41 {}^{2} - 40 {}^{2} } = \sqrt{1 \times 81} = \sqrt{81} = 9 \\ 4) \sqrt{6.8 {}^{2} - 3.2 {}^{2} } = \sqrt{ \frac{1156}{25} - \frac{256}{22} } = \sqrt{36} = 6$

$5) \sqrt{21.8 {}^{2} - 18.2 {}^{2} } = \sqrt{ \frac{11881}{25} - \frac{8281}{25} } = \sqrt{144} = 12$

Answer 2

$1) \sqrt{13^{2}-12^{2} }=\sqrt{(13-12)*(13+12)}=\sqrt{1*25}=\sqrt{25}=5\\2) \sqrt{25^{2}-24^{2} }=\sqrt{(25-24)*(25+24)}=\sqrt{1*49}=\sqrt{49}=7\\3) \sqrt{41^{2}-40^{2} }=\sqrt{(41-40)*(41+40)}=\sqrt{1*81}=\sqrt{81}=9\\4) \sqrt{6,8^{2}-3,2^{2} }=\sqrt{(6,8-3,2)*(6,8+3,2)}=\sqrt{3,6*10}=\sqrt{36}=6\\5) \sqrt{21,8^{2}-18,2^{2} }=\sqrt{(21,8-18,2)*(21,8+18,2)}=\sqrt{3,6*40}=\sqrt{144}=12$