Question

Найти производную функции y=(1-2x)/(x^2-x-6)^2

Answer 1

$y = \frac{(1 - 2x)}{(x {}^{2} - x - 6) {}^{2} }$

y'=d/dx(1-2x/(x²-x-6)²)

y'=-2(x²-x-6)²-(1-2x)•2(x²-x-6)(2x-1)/((x²-x-6)²)²

y'=6x²-6x+14/(x²-x-6)³