Question

помогите дать правильный ответ ​

Answer 1

Ответ:

$( \sqrt{32} - \sqrt{2} ) {}^{2} - \sqrt{6.4} \times \sqrt{10 } = (2 {}^{2} \sqrt{2} - \sqrt{2} ) {}^{2} - 8 = (3 \sqrt{2} ) {}^{2} - 8 = 9 \times 2 - 8 = 18 - 8 = 10$

Answer 2

$\displaystyle (\sqrt{32-\sqrt{2} })^2-\sqrt{6,4}\sqrt{10}=(2^2\sqrt{2}-\sqrt{2})-\sqrt{64}=\\ \\ (4\sqrt{2}-\sqrt{2})^2-\sqrt{64}=(4\sqrt{2}-\sqrt{2})^2-8=(3\sqrt{2})^2-8=9*2-8=18-8=10$