Question

Уравнение 10 класс
$25^x-4*5^x=0$

Answer 1

Ответ:

$25^{x}-4\cdot 5^{x}=0\\\\(5^{x})^2-4\cdot 5^{x}=0\\\\5^{x}\cdot (5^{x}-4)=0\\\\a)\ \ 5^{x}>0\\\\b)\ \ 5^{x}=4\ \ ,\ \ x=log_54\ \ ,\ \ \ x=2\, log_52\\\\Otvet:\ \ x=2\, log_52\ .$

Answer 2

${25}^{x} - 4 \times {5}^{x} = 0 \\ \\ \\ {5}^{x} \times ( {5}^{x} - 4) = 0 \\ \\ \\ {5}^{x} = 0 \\ {5}^{x} - 4 = 0 \\ \\ \\ {5}^{x} - 4 = 0 \\ \\ {5}^{x} = 4 \\ \\ x = 2 log_{5}(2) .$