Question

СРОЧНО! УМОЛЯЮ!!!!!!!111!!!!!!!!!!!11111

Answer 1

Объяснение:

$\begin{array}{l}1.\: \: (x+y+2z)(3x-2y)= \\ \: \: \: = (x+y+2z) {\cdot}3x-(x+y+2z){\cdot}2y= \\ \: \: \: =x{\cdot}3x + y{\cdot}3x + 2z{\cdot}3x - x{\cdot}2y - y{\cdot}2y - 2z{\cdot}2y = \\ \: \: \: = 3 {x}^{2} + 3xy + 6xz -2xy - 2 {y}^{2} - 4yz = \\ \: \: \: = \large {3 {x}^{2} + xy + 6xz - 2 {y}^{2} - 4yz } \\ \\ 2. \: \:(x+y^2+z)(x-z)= \\ \: \: \: = (x+y^2+z){ \cdot}x-(x+y^2+z){ \cdot}z= \\ \: \: \: = x{ \cdot}x+y^2{ \cdot}x+z{ \cdot}x - x{ \cdot}z - {y}^{2}{ \cdot}z - z{ \cdot}z = \\ \: \: \: = {x}^{2} + x {y}^{2} + xz - xz - {y}^{2}z - {z}^{2} = \\ \: \: \: = \large{ {x}^{2} + x {y}^{2} - {y}^{2}z - {z}^{2} }\: \end{array}$