Question

Упростите и решите уравнение:
${x}^{2} = \sqrt{ \sqrt{52} - 4 } \times \sqrt{ \sqrt{52} +4}$
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Answer 1

$\displaystyle\bf\\x^{2} =\sqrt{\sqrt{52} -4} \cdot\sqrt{\sqrt{52} +4} \\\\\\x^{2} =\sqrt{(\sqrt{52} -4)\cdot(\sqrt{52} +4)} \\\\\\x^{2} =\sqrt{(\sqrt{52})^{2} -4^{2} } \\\\\\x^{2} =\sqrt{52-16} \\\\\\x^{2} =\sqrt{36} \\\\\\x^{2} =6\\\\x_{1,2} =\pm \ \sqrt{6} \\\\\\Otvet:-\sqrt{6} \ \ ; \ \ \sqrt{6}$