Question

обчисліть!!!!!!!!!!! будь ласка​

Answer 1

$\displaystyle \frac{y-7}{y^2-25}:\frac{2y-14}{y+5}=\frac{y-7}{(y-5)(y+5)}*\frac{y+5}{2y-14}=\frac{y-7}{y-5}*\frac{1}{2(y-7)}=\frac{1}{y-5}*\frac{1}{2}=\\ \\ \frac{1}{2(y-5)}=\frac{1}{2y-10}$