Question

пожалуйста помогите, 8 задание даю 25 баллов​

Answer 1

$\displaystyle \bigg(\frac{y^2}{x(x^2-y^2)}+\frac{1}{x+y}\bigg):\bigg(\frac{x}{y(y+x)}-\frac{x-y}{x(x+y)}\bigg)\\\\1) \frac{y^2}{x(x-y)(x+y)}+\frac{1}{x+y}=\frac{y^2+x(x-y)}{x(x-y)(x+y)}=\frac{y^2+x^2-xy}{x(x-y)(x+y)}\\\\2)\frac{x}{y(x+y)}-\frac{x-y}{x(x+y)}=\frac{x^2-y(x-y)}{xy(x+y)}=\frac{x^2-xy+y^2}{xy(x+y)}\\\\3)\frac{y^2+x^2-xy}{x(x-y)(x+y)}*\frac{xy(x+y)}{x^2-xy+y^2}=\frac{xy(x+y)}{x(x-y)(x+y)}=\frac{y}{x-y}$

$\displaystyle y=1; x=\frac{1}{2}\\\\\frac{1}{\frac{1}{2}-1}=\frac{1}{-\frac{1}{2}}=-2$