Question

помогите пж срочно!!!!!!!​

Answer 1

$\displaystyle 1)-3xy^2*0,25x^3y*4xy=-3x^1y^2x^3y^1x^1y^1=-3x^1^+^3^+^1y^2^+^1^+^1=-3x^5y^4\\\\ 2)(-0,5ac)^2*3a^3=(0,5ac)^2*3a^3=0,5^2*a^2c^2*3a^3=(\frac{1}{2})^2*a^2c^2*3a^3=\\ \\ \frac{1}{4}a^2c^2*3a^3= \frac{3}{4}a^5c^2=0,75a^5c^2$