Question

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Answer 1

$\displaystyle \left \{ {{y-x^2=1} \atop {y-x=1}} \right.\\\\ \left \{ {{y-x^2=1} \atop {y=1+x}} \right. \\\\ 1+x-x^2=1\\x=0,x=1\\y=1+0,y=1+1\\y=1,y=2\\(x_1,y_1)=(0,1)\\(x_2,y_2)=(1,2)$