Question

Помогите прошу
Задание снизу
Даю 55 баллов

Answer 1

Ответ:

Подробное решение во вложении

Answer 2

$\displaystyle\bf\\\sqrt{18} =\sqrt{9\cdot2} =\sqrt{9} \cdot\sqrt{2} =3\sqrt{2} \\\\\\\sqrt{12} =\sqrt{4\cdot3} =\sqrt{4} \cdot\sqrt{3} =2\sqrt{3} \\\\\\\sqrt{48} =\sqrt{16\cdot3} =\sqrt{16} \cdot\sqrt{3} =4\sqrt{3} \\\\\\\sqrt{80} =\sqrt{16\cdot5} =\sqrt{16} \cdot\sqrt{5} =4\sqrt{5} \\\\\\\sqrt{125} =\sqrt{25\cdot5} =\sqrt{25} \cdot\sqrt{5} =5\sqrt{5} \\\\\\\sqrt{490} =\sqrt{49\cdot10} =\sqrt{49} \cdot\sqrt{10} =7\sqrt{10}$

$\displaystyle\bf\\\sqrt{0,72} =\sqrt{0,36\cdot2} =\sqrt{0,36} \cdot\sqrt{2} =0,6\sqrt{2}$