Question

Помогите срочно !!!! Учиру!!!!!!!

Answer 1

Ответ:

${}\ \ \ \boxed{\ a^{-1}=\dfrac{1}{a}\ \ \ ,\ \ \ a^{-k}=\dfrac{1}{a^{k}}\ }\\\\\\\\\dfrac{b^8}{m^{-9}}=b^8\cdot \dfrac{1}{m^{-9}}=b^8\cdot \dfrac{1}{\frac{1}{m^9} }=b^8\cdot m^9$