Question

Решите уравнение log5(x2+4x)=log5(x2+11)

Answer 1

$\displaystyle log_5(x^2+4x)=log_5(x^2+11), x \in (-\infty,-4)\cup(0, + \infty)\\x^2+4x=x^2+11\\4x=11\\\\ x=\frac{11}{4}=2\frac{3}{4}=2,75$