Question

разложи многочлен на множители
1)a^2(x-y)-b(x-y)
2)4(a+b)-a(a+b)+5c(a+b)
3)10a(x^2-4)-(x^2-4)
4)-7(5-c)+5c(5-c)-5c^2(5-c)

Answer 1

$\displaystyle 1)a^2(x-y)-b(x-y)=(x-y)(a^2-b)\\\\ 2)4(a+b)-a(a+b)+5c)a+b)=(a+b)(4-a+5c)\\\\3)10a(x^2-4)-(x^2-4)=(x^2-4)(10a-1)=(x-2)(x+2)(10a-1)\\\\4)-7(5-c)+5c(5-c)-5c^2(5-c)=-(5-c)(7-5c+5c^2)$