Question

Помогите с системой пожалуйста

Answer 1

$\displaystyle\bf\\\left \{ {{(x-4)(y-4)=0} \atop {\dfrac{y-2}{x+y-6}}=2} \right. \\\\\\\left \{ {{(x-4)(y-4)=0} \atop {2\cdot(x+y-6)=y-2}} \right. \\\\\\\left \{ {{(x-4)(}y-4=0 \atop {2x+2y-12=y-2}} \right. \\\\\\\left \{ {{(x-4)(y-4)=0} \atop {2x+y=10}} \right. \\\\\\\left \{ {{\left[\begin{array}{ccc}x-4=0\\y-4=0\end{array}\right \atop {2x+y=10}} \right. \\\\\\\left \{ {{\left[\begin{array}{ccc}x=4\\y=4\end{array}\right \atop {2x+y=10}} \right.$

$\displaystyle\bf\\1)\\\\\left \{ {{x=4} \atop {2x+y=10}} \right. \\\\\\\left \{ {{x=4} \atop {2\cdot 4+y=10}} \right.\\\\\\\left \{ {{x=4} \atop {8+y=10}} \right. \\\\\\\left \{ {{x=4} \atop {y=2}} \right. \\\\\\2)\\\\\left \{ {{y=4} \atop {2x+y=10}} \right. \\\\\\\left \{ {{y=4} \atop {2x+4=10}} \right. \\\\\\\left \{ {{y=4} \atop {2x=6}} \right. \\\\\\\left \{ {{y=4} \atop {x=3}} \right.\\\\\\Otvet:(4 \ ; \ 2) \ , \ (3 \ ; \ 4)$