Question

Дам много баллов!!!!

Answer 1

Ответ:

(3а+9)\а

Объяснение:

решение внизу

Answer 2

$\displaystyle\bf\\\frac{3a}{a-3}+\frac{a+5}{6-2a} \cdot\frac{54}{5a+a^{2} }= \frac{3a}{a-3}+\frac{a+5}{2(3-a)} \cdot\frac{54}{a(5+a)}= \\\\\\=\frac{3a}{a-3}-\frac{1}{a-3} \cdot\frac{27}{a}=\frac{3a}{a-3} -\frac{27}{a(a-3)} =\frac{3a\cdot a-27}{a(a-3)} =\\\\\\=\frac{3a^{2} -27}{a(a-3)} =\frac{3(a^{2} -9)}{a(a-3)} =\frac{3(a-3)(a+3)}{a(a-3)} =\frac{3a+9}{a}$