Question

Найди периметр треугольника

Answer 1

Ответ:

$A(2;1)\ ,\ B(9;4)\ ,\ C(7;6)\\\\|AB|=\sqrt{(9-2)^2+(4-1)^2}=\sqrt{7^2+3^2}=\sqrt{58}\\\\|AC|=\sqrt{(7-2)^2+(6-1)^2}=\sqrt{5^2+5^2}=\sqrt{50} =5\sqrt2\\\\|BC|=\sqrt{(7-9)^2+(6-4)^2}=\sqrt{2^2+2^2}=\sqrt{8}=2\sqrt2\\\\P=\sqrt{58}+5\sqrt2+2\sqrt2=\sqrt{58}+7\sqrt2$