Question

Задание прикреплено ниже. Весьма сложное. Заранее благодарю!

Answer 1

F(x)=-3cos(x/3))/3+(4sin(4x))/4+c;

F(x)=-cos(x/3)+sin(4х)+с

3=-cos(π/3)+sin(4π)+c;⇒с=3+0.5=3.5

F(x)=-cos(x/3)+sin(4х)+3.5

2) F(x)=-(2ctg(4x-π/12))/4+c;  

F(x)=-0.5ctg(4x-π/12)+c;

√3/2=-0.5ctg(4*π/16-π/12)+c;  

√3=-ctg(π/4-π/12)+c;

√3=-ctg(2π/12)+c;

√3=-ctg(π/6)+c;⇒c=√3+√3=2√3

F(x)=-0.5ctg(4x-π/12)+2√3;