Question

5х(7у-х)-(3х+7у)=
23а+4÷(8-3а)=
3х-5у-7х+8у=​

Answer 1

1)5х(7у-х)-(3х+7у)=35xy-5x²-(3x+7x)=35xy-5x²-10x

2)23а+4÷(8-3а)=

$23a + \frac{4}{8 - 3a} = \frac{23a \times (8 - 3a) + 4}{ 8 - 3a} = \frac{184a - 69a {}^{2} + 4 }{8 - 3a} = \frac{ - 69a {}^{2} + 184a + 4 }{8 - 3a}$

3)3х-5у-7х+8у=-4x-5y+8y=-4x+3y