Question

(5^x - 5) (16 - 2^x) / 3x = 0

Answer 1

Ответ:

$\frac{ (5^x-5)(16-2^x)}{3x}=0$

$(5^{x}-5)(16-2^x)=0$

$5^x-5=0\\16-2^x=0\\x=1\\x=4$