Question

Помогите пожалуйста!

Answer 1

$\boxed{1).}9y - 6x + 2 = 0; \Rightarrow \: \\ \Rightarrow \: 9y = 6x - 2; \Rightarrow \\ \Rightarrow \: \boxed{ \huge y = \frac{6x - 2}{9} }$

$\boxed{2).}9y - 6x + 2 = 0; \Rightarrow \\\Rightarrow \: 1).9y - 6 \bigg( - 3 \bigg) + 2 =0; \Rightarrow \\ \Rightarrow \: 9y + 20 = 0; \Rightarrow \\ \Rightarrow \: y = - \frac{20}{9} = \boxed{ \huge \: - 2.22};$

$2). \: 9y - 6 \bigg(9 \bigg) + 2 = 0 ; \Rightarrow \\ \Rightarrow \: 9y - 52= 0; \Rightarrow \\ \Rightarrow \: y = \frac{52}{9} = \boxed{ \huge \: 5.78}.$