Question

1 9/35:(1 1/5+2/3); (11 5/8+ 7 1/6):3 5/12; (8 7/12-2 5/8):2 1/6

Answer 1

$1)1\frac{9}{35}:(1\frac{1}{5}+\frac{2}{3}=\frac{44}{35}:(\frac{6}{5}+\frac{2}{3})=\frac{44}{35}:\frac{28}{15}=\frac{44}{35}\cdot\frac{15}{28}=\frac{11}{7}\cdot\frac{3}{7}=\frac{33}{49}\\2)(11\frac{5}{8}+7\frac{1}{6}):3\frac{5}{12}=((11+7)+(\frac{5}{8}+\frac{1}{6})):\frac{41}{12}=(18+\frac{19}{24})\cdot\frac{12}{41}=18\frac{19}{24}\cdot\frac{12}{41}=\frac{451}{24}\cdot\frac{12}{41}=\frac{11}{2}$

$3)(8\frac{7}{12}-2\frac{5}{8}):2\frac{1}{6}=(\frac{103}{12}-\frac{21}{8})\cdot\frac{1}{2}\cdot\frac{1}{6}=\frac{143}{24}\cdot\frac{1}{2}\cdot\frac{1}{6}=\frac{143}{288}$

Answer 2

Ответ:

Пошаговое объяснение:

1. 44/35÷ (6/5+2/3)=44/35÷ 15/28=11/7×3/7=33/49;

2. (11+7)+(5/8+1/6)÷41/12=(18+19/24)×12/41=451/24×12/41=11/2=5 1/2

3. (103/12-21/8)×1/2×1/6=143/24×1/2×1/6=143/288