Question

(4-2√3)во второй степени

Answer 1

$\tt \large { \bigg(4 - 2 \sqrt{3} \bigg)}^{2} = 16 - 16 \sqrt{3} + 12 = \boxed{ \frak{ \huge \: 28 - 16 \sqrt{3}} }.$

Answer 2

Ответ:

${}\ \ \ \boxed{\ (a-b)^2=a^2-2ab+b^2}\\\\\\(4-2\sqrt3)^2=4^2-2\cdot 4\cdot 2\sqrt3+(2\sqrt3)^2=16-16\sqrt3+4\cdot 3=28-16\sqrt3$