Question

Помогите пожалуйста добрые люди

Answer 1

Ответ:

$g(7) = \frac{1}{343} \\ g (\frac{1}{ - 4} ) = - 64 \\ g( \frac{1}{5} ) = 125$

Объяснение:

$g(x) = {x}^{ - 3} \\ g(7) = {7}^{ - 3} = \frac{1}{ {7}^{3} } = \frac{1}{343}$

$g( \frac{1}{ - 4} ) = {( \frac{1}{ - 4}) }^{ - 3} = {( { - 4)}^{ - 1}) }^{ - 3} = {( - 4)}^{ - 1 \times ( - 3)} = {( - 4)}^{3} = - 64 \\ g( \frac{1}{5} ) = {( \frac{1}{5})}^{ - 3} = {( {5}^{ - 1})}^{ - 3} = {5}^{ - 1 \times ( - 3)} = {5}^{3} = 125$

Answer 2

$g(x)=x^{-3}$

$g(1)=1^{-3}=(\frac{1}{1})^3=1$

$g(7)=7^{-3}=(\frac{1}{7})^3=\frac{1}{343}$

$g(\frac{1}{-4})=(\frac{1}{-4})^{-3}=1:(\frac{1}{-4})^3=1:(\frac{1}{-64})=-64$

$g(\frac{1}{5})=(\frac{1}{5})^-3=1:\frac{1}{5}^3=1:\frac{1}{125}=125$